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JS
Registered: 10/06/09
Posts: 18

    11/02/09 at 09:35 PM
Reply with quote#1

What would happen if a molecule had two bromine atoms? Would the relative intensity of M+2 be double that of M? Would it therefore be impossible for the molecular ion (M) to be the base peak?
DrH
Moderator
Registered: 09/22/08
Posts: 431

    11/02/09 at 09:40 PM
Reply with quote#2

M+2 intensities are additive. In other words, the mass spectrum for a molecule with two bromine atoms, when M has a relative abundance of 100%, M+2 is very nearly 200%. If one bromine and one chlorine is present, M+2 is ~135%.
jamar
Registered: 10/12/09
Posts: 17

    11/05/09 at 12:28 AM
Reply with quote#3

I understand the additive property Dr. Hardinger.  But in that situation, if M+2 were to be 200% relative to M, would we reassign M+2 as the 100% base peak and make M proportionally smaller at 50%?
dhlee624
Registered: 10/08/09
Posts: 19

    11/14/09 at 11:05 PM
Reply with quote#4

Quote:
Originally Posted by jamar
I understand the additive property Dr. Hardinger.  But in that situation, if M+2 were to be 200% relative to M, would we reassign M+2 as the 100% base peak and make M proportionally smaller at 50%?


I believe M is always set to 100% as the relative ion abundance and M+1 and M+2 are set relative to that.
DrH
Moderator
Registered: 09/22/08
Posts: 431

    11/15/09 at 08:43 AM
Reply with quote#5

We set M = 100% (regardless of the relative abundance of other peaks) to use M, M+1, and M+2 to determine molecular formula. There is no general rule that states "M is always always 100%".
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