sameerpatel
Registered: 10/03/09
Posts: 7
|
|
| |
Reply with quote | #1 |
On Question 2 of the Spring 2008 Midterm Exam 1, Lecture 2, it asks to give the number of lone pairs on nitrogen, oxygen, and any other atoms within the above structure that is drawn for you. Sulfur, which has 4 bonds and hence 8 electrons, is drawn in the structure, however the answer says that sulfur also possesses a lone pair. How are you suppose to know that in this particular case sulfur breaks the octet rule and has 10 electrons around it?
|
| Loading... | | |
sunghyunlim
Registered: 10/25/09
Posts: 6
|
|
| |
Reply with quote | #2 |
In that case, the surfur atom should have a formal charge on it (should be given in the problem).
|
| Loading... | | |
gloomfilter
Registered: 09/27/09
Posts: 25
| |
gbobarnac
Registered: 10/24/09
Posts: 14
|
|
| |
Reply with quote | #4 |
sulfur tends to always accomodate more than 8 electrons. it usually has 5-6 attachments, so 10-12 electrons
so if you make the formal charge to be zero you have 0= 6valence e - 1/2(8 bonding electrons) - lone electrons which gives you lone electrons=2 which is one lone pair.
|
| Loading... | | |
DrH
Moderator
Registered: 09/22/08
Posts: 437
|
|
| |
Reply with quote | #5 |
Sulfur has four attachments more frequently than is has five or six attachments. In H2SO4 sulfur has four oxygen attachments. |
| Loading... | | |
