c2ecila
Registered: 10/21/09
Posts: 13
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PurplePpleEator
Registered: 10/04/09
Posts: 41
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Reply with quote | #2 |
There is only an ester group and an alkene. The reason that it is not an aldehyde is because the Carbon is not bonding to a hydrogen as well. Rather it is just double bonded to an oxygen and then another Carbon and Oxygen.
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c2ecila
Registered: 10/21/09
Posts: 13
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Reply with quote | #3 |
i was thinking about the C=O,C-H off of the amide....Nitrogen is connected to a C with an O and H... |
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PurplePpleEator
Registered: 10/04/09
Posts: 41
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Reply with quote | #4 |
I apologize I looked at 13a.
I believe the reasoning behind it is that an aldehyde has a carbon double bonded to an oxygen, single bonded to a hydrogen (which are both present) and then connected to a side chain, usually represented by a R group. Typically this R group is a carbon group and since the carbon is connected to a Nitrogen it does not fit this qualification.
To me this is the best reasoning behind it, but I would still recommend looking into it and seeing if someone else knows more about this topic.
Once again sorry for the mix-up.
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PurplePpleEator
Registered: 10/04/09
Posts: 41
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Reply with quote | #5 |
In addition to that I found on Spring 2009 Exam 1 that Dr. H said that We do not say that a more complex functional group contains a simpler functional group.
On question 2, so that might be a more accurate reason why we ignore it.
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